If one bag of food lasts a dog 6 days, what is the smallest number of bags needed for 18 days? - briefly
To determine the smallest number of bags required to feed a dog for 18 days, given that one bag lasts 6 days, we calculate the total number of bags by dividing the total duration by the duration covered by one bag. This results in ( \frac{18}{6} = 3 ) bags. Thus, three bags are needed to feed the dog for 18 days.
If one bag of food lasts a dog 6 days, what is the smallest number of bags needed for 18 days? - in detail
To determine the smallest number of bags required to feed a dog for 18 days, given that one bag of food lasts 6 days, we need to perform a simple calculation based on proportionality.
Firstly, let's establish the rate at which the food is consumed:
- One bag of food lasts 6 days.
Next, we calculate how many bags are needed for 18 days:
- The total number of days required is 18 days.
- To find out how many 6-day periods fit into 18 days, we divide the total days by the duration one bag lasts: ( \frac{18}{6} = 3 ).
This means that for every 6 days, one bag is needed. Therefore, to cover 18 days, which consists of three 6-day periods, you would need three bags of food.
In conclusion, the smallest number of bags required to feed a dog for 18 days is three bags.